Răspuns:
Explicație pas cu pas:
[tex]a)~\bigg(\dfrac{4}{7} \bigg)^{9}:\bigg(\dfrac{4}{7} \bigg)^{5}=\bigg(\dfrac{4}{7} \bigg)^{9-5}=\red{\bigg(\dfrac{4}{7} \bigg)^{4}}[/tex]
---------------------------------------------------
[tex]b)~\bigg(\dfrac{3}{18} \bigg)^{17}:\bigg(\dfrac{3}{18} \bigg)^{1}=\bigg(\dfrac{3}{18} \bigg)^{17-1}=\bigg(\dfrac{3^{(3}~}{18} \bigg)^{16}=\purple{\bigg(\dfrac{1}{6} \bigg)^{16}}[/tex]
---------------------------------------------------
[tex]c)~\bigg(\dfrac{2}{11} \bigg)^{23}:\bigg(\dfrac{2}{11} \bigg)^{15}=\bigg(\dfrac{2}{11} \bigg)^{23-15}=\blue{\bigg(\dfrac{2}{11} \bigg)^{8}}[/tex]
---------------------------------------------------
[tex]d)~\bigg(2\dfrac{3}{5} \bigg)^{31}:\bigg(2\dfrac{3}{5} \bigg)^{18}:\bigg(2\dfrac{3}{5} \bigg)^{6}=\bigg(2\dfrac{3}{5} \bigg)^{31-18-6}=\green{\bigg(2\dfrac{3}{5} \bigg)^{7}}[/tex]
⋆ Formule pentru puteri:
[tex]\red{ \bf a^{0} = 1}[/tex]
[tex]\red{\bf (a^{n})^{m} = a^{n \cdot m}}[/tex]
[tex]\red{\bf a^{n}\cdot a^{m} =a^{n+m}}[/tex]
[tex]\red{ \bf a^{n}: a^{m} =a^{n-m}}[/tex]
