[tex]\it \dfrac{2x-3y}{x-2y}=\dfrac{8}{7} \Rightarrow 14x-21y=8x-16y \Rightarrow 14x-8x=21y-16y \Rightarrow 6x=5y \Rightarrow\\ \\ \\ \Rightarrow y=\dfrac{6}{5}x \Rightarrow y=1,2x\ \ \ \ \ (*)[/tex]
[tex]\it \dfrac{3x+y}{4y-3x}\ \stackrel{(*)}{=}\ \dfrac{3x+1,2x}{4\cdot1,2x-3x}=\dfrac{4,2x}{1,8x}=\dfrac{\ 42^{(6}}{18}=\dfrac{7}{3}[/tex]
