Răspuns:
1.
[tex](7 x + 1) \times ( - 2x + 2) - (2x + 3) {}^{2} = - 14 {x}^{2} + 14x - 2x + 2 - (4 {x}^{2} + 12x + 9) = - 14 {x}^{2} + 14x - 2x + 2 - 4 {x}^{2} - 12x - 9 = - 18 {x}^{2} + 0 - 7 = - 18 {x}^{2} - 7[/tex]
2.
[tex](4x + 6) \times (3x + 1) - (2x + 1) {}^{2} = 12 {x}^{2} + 4x + 18x \div 6(4 {x}^{2} + 4x + 1) = 12 {x}^{2} + 4x + 18x + 6 - 4 {x}^{2} - 4x - 1 = 8 {x}^{2} + 18x + 5[/tex]
