Răspuns:
Explicație pas cu pas:
[tex]\bf a)~~\dfrac{\not 3}{\not 5}\cdot \dfrac{\not 10}{\not 9}\cdot \dfrac{15}{\not 2} = \dfrac{1}{1}\cdot \dfrac{1}{\not3}\cdot \dfrac{\not15}{1} = \red{\underline{5}}[/tex]
[tex]\bf b)~~3\dfrac{1}{2}\cdot \dfrac{\not4}{7}\cdot \dfrac{1}{\not 4} = \dfrac{\not7}{2}\cdot \dfrac{1}{\not7}\cdot \dfrac{1}{1} = \purple{\boxed{\bf \dfrac{1}{2}}}[/tex]
[tex]\bf c)~~2\dfrac{1}{3}\cdot \dfrac{6}{7}\cdot 1\dfrac{1}{ 2} = \dfrac{\not7}{\not3}\cdot \dfrac{\not6}{\not7}\cdot \dfrac{\not3}{\not2} = \dfrac{1}{1}\cdot \dfrac{3}{1}\cdot \dfrac{1}{1} = \blue{\underline{3}}[/tex]
[tex]\bf d)~~\dfrac{ 5}{6}\cdot3 \dfrac{4}{5}\cdot \dfrac{30}{19} = \dfrac{ \not5}{\not6}\cdot \dfrac{\not19}{\not5}\cdot \dfrac{\not30}{\not19} =\dfrac{1}{1}\cdot \dfrac{1}{1}\cdot \dfrac{5}{1} = \pink{\underline{5}}[/tex]
==pav38==
