Răspuns:
Explicație pas cu pas:
[tex]\frac{x-4}{x+6} =(x-6)^{2} -4\\\frac{x-4}{x+6}=(x-6-2)(x-6+2)\\\frac{x-4}{x+6}=(x-8)(x-4)\\\frac{x-4}{x+6}-(x-8)(x-4)=0\\(x-4)(\frac{1}{x+6} -x+8)=0\\x-4=0\\x=4\\\\\frac{1}{x+6} -x+8=0[/tex]
1-x(x+6)+8(x+6)=0
1-x²-6x+8x+48=0
-x²+2x+49=0
x²-2x-49=0
Δ=200
[tex]x_{1}=\frac{2+10\sqrt{2} }{2} =1+5\sqrt{2} \\x_{2}=\frac{2-10\sqrt{2} }{2} =1-5\sqrt{2}[/tex]