Răspuns:
prima problemă
a+b=40
a= b×3
a |........|........|..........| 40
b, |..........|
40÷4=10 (b)
10×3=30 (a)
a două problemă
|.......|........|.........|...........|......... |.........| a
|.......| b
45÷5=9(b)
9×6=54 (a)
problema a treia
|...........| a
|..........|......... |b+72
140÷72=68
1×68=68,(a)
2×68+72=136+72=208(b)
problema a patra
a-a÷3=100
a|........|
b |.......|.......|..........|
100
100÷2=50(a÷3)
a=50×3
a=150
