Răspuns:
[tex]\displaystyle\\\rm\\Presiunea = 2,5 \cdot 10^{5} \ pascali[/tex]
Explicație:
[tex]\displaystyle\\\rm\\\nu = 2 \ moli \\ \\t = 29^\circ \ C = 29 + 273 = 302 \ K \\ \\V = 20 \ l = 20 \cdot 10^{-3} \ m^3 \\ \\p \cdot V = \nu \cdot R \cdot T \implies p = \frac{\nu \cdot R \cdot T}{V} \\ \\p = \frac{2\cdot 8,31 \cdot 302}{20 \cdot 10^{-3}} = 250.962 \ Pa[/tex]
