Răspuns:
a) 2¹⁵:2¹³+3x[(2²)²+3x(3²+3¹⁷:3¹⁶)] =
2¹⁵⁻¹³+3×[(2²ˣ²+3×(9+3¹)]=
2²+3×(2⁴+36)=
2²+3×(16+36)=
4+3×52=
4+156=
160
b) 3¹⁷:(3⁵)⁵+2x[(3²)²+2x(2³+2¹⁶:2¹⁷)]=
3¹⁷⁻²⁵+2×[3⁴+2×(8+2⁻¹)]=
3⁻⁸+2×[81+2×(²⁾8+1/2)=
1/3⁸+2×(81+2×17/2)=
1/3⁸+2×98= cred ca ex a fost scris gresit
