pls rezolvati exercitiul 1 si 4

[tex]\it 1) \ \ \ =140:25-2:4+1=5,62-0,5+1=6,12\\ \\ \\ 4)\ \dfrac{2}{5}\cdot200=2\cdot40=80\ km\ (prima\ zi)\\ \\ \\ \dfrac{30}{100}\cdot200=30\cdot2=60\ km\ (a\ doua\ zi)\\ \\ \\ 200-(80+60)=200-140=60\ km\ (a\ treia\ zi)[/tex]