Răspuns:
Explicație pas cu pas:
Partea I
1.
-7/9
2.
-3,7 = -37/10
I-37/10I = 37/10
3.
a = -5/3 = -20/12
b = -7/4 = -21/12
a > b
Partea a II-a
1.
2,(3) = (23 - 2)/9 = 21/9 = 7/3
7/3 - 2,(3) = 7/3 - 7/3 = 0
2.
25/7*42/50 = 1/7*42/2 = 1/7*21/1 = 21/7 = 3
3.
(-3/5)^5 : (-3/5)^3 = (-3/5)^2 = 9/25
Partea a III-a
1.
a = (21/10 + 1/2) : 13/4 - 6/5 + 0,4 = (21/10 + 5/10) *4/13 - 6/5 + 4/10
= 26/10*4/13 - 6/5 + 2/5 = 4/5 - 6/5 + 2/5 = 0
b = (5/3)^5 *[(5/3)^2]^7 : (5/3)^16 =(5/3)^5 *(5/3)^14 : (5/3)^16
= (5/3)^19 : (5/3)^16 = (5/3)^3 = 125/27
2.
a = (3/4 - 1)*(-0,2) + 3/2 = (3/4 - 4/4)*(-2/10) + 3/2 = -1/4*(-1/5) + 3/2
= 1/20 + 30/20 = 31/20
b = 15/82 - 15/82*41/3 : 5/2 = 15/82 - 5/2 : 5/2 = 15/82 - 1 = 15/82 - 82/82
= -67/82
a > b
3.
(-5/4)^-2 : (-5/4)^-6 *[(-5/4)^2]^3 = (-5/4)^4 : (-5/4)^6 = (-5/4)^-2
inversul este (-5/4)^2
