Explicație pas cu pas:
[tex]a+b+c=52 \\ 2a=3b=4c = k[/tex]
=>
[tex]2a = k = > a = \frac{k}{2} \\ 3b = k = > b = \frac{k}{3} \\ 4c = k = > c = \frac{k}{4} [/tex]
=>
[tex]\frac{k}{2} + \frac{k}{3} + \frac{k}{4} = 52 \\ \frac{6k + 4k + 3k}{12} = 52 [/tex]
[tex] \frac{13k}{12} = 52 = > k = 48 \\ [/tex]
=>
[tex]a = \frac{48}{2} = > a = 24 \\ b = \frac{48}{3} = > b = 16 \\ c = \frac{48}{4} = > c = 12[/tex]
