Răspuns:
Aria trapez:
A = (b+B)*h/2
b= n
B= n+1
h = n+2
A=(n+n+1)*(n+2)/2
A=(2n+1)*(n+2)/2
(2n+1)*(n+2)=2A
(2n+1)*(n+2) = 2*52
(2n+1)*(n+2) = 104
(2n+1)(n+2)=13*8
2n+1=13 => n=6
n+2=8 => n=6
Distanta intre baze este tocmai inaltimea:
h=n+3=6+3 = 9 cm
Explicație pas cu pas: