[tex]\it Fie\ a\ \d si\ b\ cele\ dou\breve a\ numere.\\ \\ a+b=-8 \Rightarrow a= -8-b \Rightarrow |a|=|-8-b| \Rightarrow |a|=|8+b| \ \ \ \ \ (1)\\ \\ \dfrac{|a|}{|b|}=2,(3)=2\dfrac{3}{9}=\dfrac{\ 21^{(3}}{9}=\dfrac{7}{3} \Rightarrow |a|=\dfrac{7}{3}\cdot|b|\ \ \ \ \ (2) \\ \\ \\ (1),\ (2)\Rightarrow |8+b|=\dfrac{7}{3}|b|\Rightarrow8+b=\pm\dfrac{7}{3}b|_{\cdot3} \Rightarrow 24+3b=\pm7b\\ \\ I)\ 24+3b=-7b \Rightarrow 3b+7b=-24 \Rightarrow 10b=-24 \Rightarrow b=-2,4\not\in\mathbb{Z}[/tex]
[tex]\it II)\ 24+3b=7b \Rightarrow 24=7b-3b \Rightarrow 24=4b \Rightarrow b=24:4 \Rightarrow b=6\\ \\ a=-8-b=-8-6=-14[/tex]
Numerele cerute sunt -14 și 6.
