Răspuns:
14)
Explicație pas cu pas:
a)
[tex] |x| = 1 \implies \\ x = - 1 ; \ \ x = 1[/tex]
A = {-1; 1}
b)
[tex] \sqrt{2} < x < \sqrt{10} \\ 1 < \sqrt{2} < 2 \\ 3 < \sqrt{10} < 4 \\ \iff 1 < x < 4[/tex]
B = {2; 3}
c)
[tex] |x + 1| = 3 \\ x + 1 = - 3 \implies x = - 4 ∉ \mathbb{N}\\ x + 1 = 3 \implies x = 2[/tex]
C = {2}
d)
[tex]|x + 1| = \sqrt{2} \\ x + 1 = - \sqrt{2} \implies x = - \sqrt{2} - 1\\ x + 1 = \sqrt{2} \implies x = \sqrt{2} - 1[/tex]
D = {-√2 - 1; √2 - 1}
