Explicație pas cu pas:
a)
[tex]\frac{7}{ \sqrt{12} } = \frac{7}{ 2\sqrt{3}} = \frac{7 \times \sqrt{3} }{2 \sqrt{3} \times \sqrt{3} } = \frac{7 \sqrt{3} }{6} \\ [/tex]
b)
[tex]\frac{5}{ \sqrt{18} } = \frac{5}{3 \sqrt{2}} = \frac{5 \sqrt{2} }{3 \sqrt{2} \times \sqrt{2} } = \frac{5 \sqrt{2} }{6} \\ [/tex]
c)
[tex]\frac{8}{ \sqrt{24} } = \frac{8}{2 \sqrt{6} } = \frac{4 \sqrt{6} }{ \sqrt{6} \times \sqrt{6} } = \frac{4 \sqrt{6} }{6} = \frac{2 \sqrt{6} }{3} \\ [/tex]
d)
[tex]\frac{14}{ \sqrt{63} } = \frac{14}{3 \sqrt{7} } = \frac{14 \sqrt{7} }{3 \sqrt{7} \sqrt{7} } = \frac{14 \sqrt{7} }{21} = \frac{2 \sqrt{7} }{3} \\ [/tex]
e)
[tex]\frac{ - 4}{3 \sqrt{32} } = \frac{ - 4}{3 \times 4\sqrt{2} } = - \frac{ \sqrt{2} }{3 \sqrt{2} \times \sqrt{2} } = - \frac{ \sqrt{2} }{6} \\ [/tex]
f)
[tex]\frac{35}{5 \sqrt{28} } = \frac{7}{2 \sqrt{7} } = \frac{7 \sqrt{7} }{2 \sqrt{7} \times \sqrt{7} } = \frac{7 \sqrt{7} }{14} = \frac{ \sqrt{7} }{2} \\ [/tex]
