Răspuns:
a)
[tex] {1}^{0} \times {1}^{1} \times {1}^{2} \times ... \times {1}^{20} = \\ = {1}^{1 + 2 + 3 + ... + 20} = \\ \\ = {1}^{20 \times 21 \div 2} = \\ = {1}^{10 \times 21} = \\ = {1}^{210} = \\ = 1[/tex]
b)
[tex]2 + {2}^{2} \times 3 \div 6 + 2 \times (2 + {2}^{2} \times ( {3}^{2} + 2 \times {5}^{2} \div 10 - 9)^{2} ) \div 51 = \\ = 2 + 12 \div 6 + 2 \times (2 + 4(9 + 50 \div 10 - 9)^{2} ) \div 51 = \\ = 2 + 2 + 2(2 + 4 \times {5}^{2} ) \div 51 = \\ = 4 + 2(2 + 100) \div 51 = \\ = 4 + 2 \times 102 \div 51 = \\ = 4 + 2 \times 2 = \\ = 4 + 4 = \\ = 8[/tex]
Succes!
