ajutor plz repedeewwwe c

Răspuns:
Explicație pas cu pas:
6 + 12 + 18 + 24 + ... + 600 = 6*(1 + 2 + 3 + 4 + ... + 100)
= 6*100*101/2 = 3*100*101 = 300*101
3 + 6 + 9 + 12 + ... + 300 = 3*(1 + 2 + 3 + 4 + ... + 100)
= 3*100*101/2 = 3*50*101 = 150*101
1 + 2 + 3 + ... + 100 = 100*101/2 = 50*101
_____________
(300*101)^2 = 300*300*101*101
300*300*101*101 : 150*101 = 300*2*101 = 600*101
600*101 : 50*101 = 12
Răspuns:
12
Explicație pas cu pas:
f)
[tex]{(6 + 12 + 18 + 24 + ... + 600)}^{2} : (3 + 6 + 9 + 12 + ... + 300) : (1 + 2 + 3 + ... + 100) = \\ [/tex]
[tex]= { \Big[6 \cdot\Big(\underbrace{1 + 2 + 3 + ... + 100}_{S}\Big)\Big]}^{2} : \Big[3 \cdot \Big(\underbrace{1 + 2 + 3 + ... + 100}_{S}\Big)\Big] : \Big(\underbrace{1 + 2 + 3 + ... + 100}_{S}\Big) \\ [/tex]
[tex]= 36 {S}^{2} : (3S) : S = 36 {S}^{2} : (3S \cdot S) \\ [/tex]
[tex]= 36 {S}^{2} : (3 {S}^{2}) = 36 : 3 = \bf 12[/tex]