Răspuns:
Alesia 6
Explicație pas cu pas:
[tex]a = \frac{ \sqrt{27} - 3}{ \sqrt{3} } = \frac{\sqrt{27}}{ \sqrt{3} } - \frac{^{ \sqrt{3} )} 3}{ \sqrt{3} } = \frac{3\sqrt{3}}{ \sqrt{3} } - \frac{3 \sqrt{3} }{3} \\ a = 3 - \sqrt{3} [/tex]
[tex]b = 18 + 3 \sqrt{12} = 18 + 6 \sqrt{3} \\ b = 6(3 + \sqrt{3})[/tex]
[tex]m_{g} = \sqrt{a \cdot b} = \sqrt{6 \cdot (3 - \sqrt{3}) \cdot (3 + \sqrt{3})} = \\ = \sqrt{6 \cdot (9 - 3)} = \sqrt{6 \cdot 6} = \sqrt{ {6}^{2} } = \bf 6[/tex]
