Explicație pas cu pas:
a)
[tex]3 \sqrt{2} - 6 = \sqrt{18} - \sqrt{36} < 0 \\ \implies |3 \sqrt{2} - 6| = 6 - 3 \sqrt{2}[/tex]
[tex]x = \sqrt{10}\Big( \frac{2}{ \sqrt{2} } + \frac{3}{ \sqrt{5} } \Big) + |3 \sqrt{2} - 6| = \\ = \frac{2 \sqrt{2 \cdot 5} }{ \sqrt{2} } + \frac{3 \sqrt{2 \cdot 5} }{ \sqrt{5} } + 6 - 3 \sqrt{2} \\ = 2 \sqrt{5} + 3 \sqrt{2} + 6 - 3 \sqrt{2} = \bf 2 \sqrt{5} + 6[/tex]
b)
[tex]y = 4 + \frac{10}{ \sqrt{5} } + {( \sqrt{3} )}^{2} = 4 + \frac{10 \sqrt{5} }{5} + 3 = \\ = \bf 2 \sqrt{5} + 7[/tex]
[tex]{(x - y)}^{2020} = {(2 \sqrt{5} + 6 - 2 \sqrt{5} - 7)}^{2020} = \\ = {( - 1)}^{2020} = {1}^{2020} = \bf 1 [/tex]
