Răspuns:
sol1:
d=ms/v=>ms=278g sol.1
CM=n/v=>n=0.4moli HNO3=>md=25,2g pure
sol2:
v=300/1,15=0,26L
md=0,2×300=60g pure, n=0,95moli
a)md final=25,2+60=85,2g pure
ms=278+300+200=778=>c=10,95%
b)n final=0,4+0.95=1,35moli HNO3
CM=n/v=>v =0,2+0,26+0,2=0,66L
CM=1,35/0,66=2,04M